0=13-3p+p^2

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Solution for 0=13-3p+p^2 equation: 



0=13-3p+p^2

We move all terms to the left:

0-(13-3p+p^2)=0

We add all the numbers together, and all the variables

-(13-3p+p^2)=0

We get rid of parentheses

-p^2+3p-13=0

We add all the numbers together, and all the variables

-1p^2+3p-13=0

a = -1; b = 3; c = -13;
Δ = b2-4ac
Δ = 32-4·(-1)·(-13)
Δ = -43
Delta is less than zero, so there is no solution for the equation

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